SOLUTION: Suppose probability of a person to have type AB is 6%. Pick 5 people at random then Find the probability that exactly one to have type AB? List all combinations? Find the prob

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Question 1115183: Suppose probability of a person to have type AB is 6%.
Pick 5 people at random then
Find the probability that exactly one to have type AB? List all combinations?
Find the probability that none to have type AB? List all combinations?
Find the probability that exactly 2 to have type AB? (you should get 10 combinations?) Show your combinations first then your answer?
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Y-Person has type AB
n-Person does not have type AB
.
.
Five possible combinations,
Ynnnn
nYnnn
nnYnn
nnnYn
nnnnY
So,
P%28X=1%29=5%2A%280.06%29%280.94%29%280.94%29%280.94%29%280.94%29=0.2342
.
.
.
Only one combination,
nnnnn
So,
P%28X=0%29=1%2A%280.94%29%280.94%29%280.94%29%280.94%29%280.94%29=0.7339
.
.
.
Ten possible combinations,
YYnnn
YnYnn
YnnYn
YnnnY
.
nYYnn
nYnYn
nYnnY
.
nnYYn
nnYnY
.
nnnYY
P%28X=2%29=10%2A%280.06%29%280.06%29%280.94%29%280.94%29%280.94%29=0.00299