SOLUTION: Cindy invested $24,000 for one year, part at 6% and part at 9%. If the total amount of interest she earned was $1,740, how much money did he invest at each rate?

Algebra ->  Customizable Word Problem Solvers  -> Finance -> SOLUTION: Cindy invested $24,000 for one year, part at 6% and part at 9%. If the total amount of interest she earned was $1,740, how much money did he invest at each rate?       Log On

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Question 1115137: Cindy invested $24,000 for one year, part at 6% and part at 9%. If the total amount of interest she earned was $1,740, how much money did he invest at each rate?

Answer by addingup(3677) About Me  (Show Source):
You can put this solution on YOUR website!
0.06x + 0.09(24,000-x) = 1,740
0.06x + 2160 - 0.09x = 1740
-0.03x = -420
x = 14,000
She invested 14,000 at 6% and 10,000 at 9%
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Check:
14,000*0.06 = 840
10,000*0.09 = 900
. . . . . . .-----
Total . . . $1,740 Correct