SOLUTION: Solve for the exact solutions over the interval (0°, 360°] Round to the nearest tenth when necessary. {{{ sec^2(theta)tan(theta) = 2tan(theta) }}}

Algebra ->  Trigonometry-basics -> SOLUTION: Solve for the exact solutions over the interval (0°, 360°] Round to the nearest tenth when necessary. {{{ sec^2(theta)tan(theta) = 2tan(theta) }}}       Log On


   

Question 1114997: Solve for the exact solutions over the interval (0°, 360°]
Round to the nearest tenth when necessary.
+sec%5E2%28theta%29tan%28theta%29+=+2tan%28theta%29+

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
+sec%5E2%28theta%29tan%28theta%29+=+2tan%28theta%29+
+tan%28theta%29%28sec%5E2%28theta%29-2%29=0+
First part,
tan%28theta%29=0
theta=0 and theta=180
Second part,
sec%5E2%28theta%29-2=0
sec%5E2%28theta%29=2
sec%28theta%29=0+%2B-+sqrt%282%29
cos%28theta%29=0+%2B-+1%2Fsqrt%282%29
cos%28theta%29=0+%2B-+sqrt%282%29%2F2
theta=%281%2F4%29pi, theta=%283%2F4%29pi, theta=%285%2F4%29pi, and theta=%287%2F4%29pi