SOLUTION: Find: sin (s+t), cos (s-t), tan (s+t), the quadrant of (s+t)
Given: {{{ sin s = 3/5 }}} and {{{sin t = -12/13}}} and that s∈QI and t∈QIII
For my work I started o
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-> SOLUTION: Find: sin (s+t), cos (s-t), tan (s+t), the quadrant of (s+t)
Given: {{{ sin s = 3/5 }}} and {{{sin t = -12/13}}} and that s∈QI and t∈QIII
For my work I started o
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Question 1114895: Find: sin (s+t), cos (s-t), tan (s+t), the quadrant of (s+t)
Given: and and that s∈QI and t∈QIII
For my work I started off with sum and difference identities
for ==== sin (s+t)
sin (s+t)=
sin (s+t)=
sin (s+t) =
for ==== cos (s-t)
cos (s-t) =
cos (s-t) =
for ==== tan (s+t)
tan (s+t) =
tan (s+t) =
for quadrant of (s+t) I would infer Q2.
from my work I think I messed up on sin t = -12/13 with the negative symbols, but I'm not sure and any help would be appreciated! Answer by ikleyn(52800) (Show Source):
Find: sin (s+t), cos (s-t), tan (s+t), the quadrant of (s+t)
Given: and and that s∈QI and t∈QIII
For my work I started off with sum and difference identities
for ==== sin (s+t)
sin (s+t)= <<<---=== cos(t) = -5/13
sin (s+t)=
sin (s+t) = <<<---=== correct
for ==== cos (s-t)
cos (s-t) =
cos (s-t) = <<<---=== correct
for ==== tan (s+t)
<<<---=== tan(t) = 12/5, and FIX everything that follows
tan (s+t) =
tan (s+t) =
for quadrant of (s+t) I would infer Q2.
from my work I think I messed up on sin t = -12/13 with the negative symbols, but I'm not sure and any help would be appreciated!
