SOLUTION: Five different algebra textbooks, two different calculus textbooks, and four different geometry textbooks are to be arranged on a shelf. How many different arrangements are possibl

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Question 1114856: Five different algebra textbooks, two different calculus textbooks, and four different geometry textbooks are to be arranged on a shelf. How many different arrangements are possible if the books of each subject must be kept together?
Found 2 solutions by stanbon, math_helper:
Answer by stanbon(75887) (Show Source):
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Five different algebra textbooks, two different calculus textbooks, and four different geometry textbooks are to be arranged on a shelf. How many different arrangements are possible if the books of each subject must be kept together?
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# of arrangements within each set:: 5!*2!*4! = 120*2*24 = 5760
# of arrangements of the sets:: 3! = 6
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Ans: 6*5760 = 34560
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Cheers,
Stan H.
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Answer by math_helper(2461) (Show Source):
You can put this solution on YOUR website!

Algebra books: 5! arrangements
Calculus books: 2! arrangements
Geometry books: 4! arrangements
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Finally, the three categories of books can be arranged in 3! ways while still keeping each subject grouped together.
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Ans: The total number of arrangements = 5!*2!*4!*3! = 120*2*24*6 =
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