SOLUTION: you decide to make homemade dried apricots and purchased 10 pounds of fresh apricots at the farmer's market. when the apricots were fresh, 85% of their weight was water. after 12 h

Algebra ->  Percentage-and-ratio-word-problems -> SOLUTION: you decide to make homemade dried apricots and purchased 10 pounds of fresh apricots at the farmer's market. when the apricots were fresh, 85% of their weight was water. after 12 h      Log On


   



Question 1114722: you decide to make homemade dried apricots and purchased 10 pounds of fresh apricots at the farmer's market. when the apricots were fresh, 85% of their weight was water. after 12 hours of drying in your excalibur dehydrator, a test showed that the water content of the apricots was now 25% by weight. how many pounds did the apricots weigh after 12 hours in the dehydrator
Found 2 solutions by ikleyn, josgarithmetic:
Answer by ikleyn(52785) About Me  (Show Source):
You can put this solution on YOUR website!
.
We are given that 


0.85*10 = 8.5 pounds is the water content in 10 pounds of fresh apricots before drying. Hence, 1.5 pounds is the fiber mass with no water.


Let x be the water content in the apricots after drying. Then the condition says that


x%2F%281.5+%2B+x%29 = 0.25.


Simplify and solve this equation for x:
  

x = 0.25x + 0.25*1.5


x - 0.25x = 0.25*1.5  ====>  0.75x = 0.25*1.5  ====>  x = %280.25%2A1.5%29%2F0.75 = 0.5.


Thus the water content in the dried apricots is 0.5 pound.


With  1.5 pounds of the dry part it is 1.5 + 0.5 = 2 pounds altogether.


Now the answer to the question  "how many pounds did the apricots weigh after 12 hours in the dehydrator"  is  2 pounds.


Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Put attention on the concentrations of water.
If Q is quantity of water removed, as pounds,
%2810%2A0.85-Q%29%2F%2810-Q%29=0.25
-
8.5-Q=0.25%2810-Q%29
34-4Q=10-Q
24=3Q
Q=8
-
The original 10 pounds fresh apricots became 2 pounds after DRYING to 25% water.