SOLUTION: Solve and check each of the following problems using the substitution method. x=1/5y 3x+2y=26 If someone could explain how to solve this step by step to me would be really nice,

Algebra ->  Numeric Fractions Calculators, Lesson and Practice -> SOLUTION: Solve and check each of the following problems using the substitution method. x=1/5y 3x+2y=26 If someone could explain how to solve this step by step to me would be really nice,      Log On


   



Question 111469: Solve and check each of the following problems using the substitution method.
x=1/5y
3x+2y=26
If someone could explain how to solve this step by step to me would be really nice, because my math teacher doesn’t really explain much and if you ask her something she says “you should have listened”. The only problem is there isn’t much to listen to since she doesn’t explain much.

Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!
The substitution method requires solving one equation for one variable in terms of the other, then substituting the derived expression for that variable into the second equation.
:
x=%281%2F5%29y
3x%2B2y=26
:
Step 1: Solve one of the equations for x in terms of y, or y in terms of x. It doesn't matter which, though sometimes, because of the way the equation is presented, one may be easier than the other. In this case, your equation 1 is already solved for x in terms of y, and nothing could be easier than doing nothing, right?
:
Step 2: Now that you have an expression for x in terms of y: x=%281%2F5%29y,
you can substitute that expression in place of x in the other equation, thus:
3x%2B2y=26
3%28y%2F5%29%2B2y=26
3y%2B10y=130
13y=130
y=10
:
Step 3: Now that we know the value of y, we can substitute that value into either of the equations to obtain the value of x.
x=%281%2F5%29y
x=%281%2F5%2910
x=2
:
Step 4: VERY IMPORTANT. Check your answer.
Does 2=%281%2F5%2910? Yes! And,
Does 3%282%29%2B2%2810%29=26? Yes! So your answers check.
:
Just to show you that it doesn't matter which variable you solve for or which equation you use in Step 1, let's do it another way and see if we get the same answers.
:
x=%281%2F5%29y
3x%2B2y=26
:
Solving equation 2 for y:
2y=26-3x
y=13-3x%2F2
:
Substituting and solving:
x=%281%2F5%29%2813-3x%2F2%29
x=13%2F5-3x%2F10
x%2B3x%2F10=13%2F5
%2810x%2B3x%29%2F10=26%2F10
13x=26
x=2
:
Substitute again and solve:
3%282%29%2B2y=26
2y=26-6
2y=20
y=10
:
And these are the same answers obtained before.