SOLUTION: Without using a graphing calculator, how do you graph logy-log((x-3))=log((x+3))

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Question 1114646: Without using a graphing calculator, how do you graph logy-log((x-3))=log((x+3))
Found 2 solutions by stanbon, ikleyn:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
logy-log((x-3))=log((x+3))
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log[y/(x-3)] = log(x+3)
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y/(x-3) = (x+3)
y = x^2+9
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graph%28400%2C400%2C-3%2C3%2C0%2C20%2Cx%5E2%2B9%29
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Cheers,
Stan H.



Answer by ikleyn(52798) About Me  (Show Source):
You can put this solution on YOUR website!
.

log(y) - log(x-3) = log(x+3)  ====>  the domain of this equation is  x > 3


log(y) = log(x+3) + log(x-3)

log(y)  = log((x+3)*(x-3))   ====>


y = (x+3)*(x-3)    in the domain  x > 3.

y = x^2 - 9       in the domain  x > 3


So the plot is the branch of the parabola y = x^2 - 9  over the domain  x > 3.

The other's tutor solution is INCORRECT.