SOLUTION: The children AL, Betty, Chuck, Dahlia, Ed, Frank and George will sit in adjacent chairs. Dahlia must be in the middle chair, and George must be next to Dahlia. In how many order ca

Algebra ->  Probability-and-statistics -> SOLUTION: The children AL, Betty, Chuck, Dahlia, Ed, Frank and George will sit in adjacent chairs. Dahlia must be in the middle chair, and George must be next to Dahlia. In how many order ca      Log On


   



Question 1114611: The children AL, Betty, Chuck, Dahlia, Ed, Frank and George will sit in adjacent chairs. Dahlia must be in the middle chair, and George must be next to Dahlia. In how many order can they be arranged
Answer by greenestamps(13219) About Me  (Show Source):
You can put this solution on YOUR website!


Seat them in an order that first satisfies the requirements....

Dahlia: 1 choice -- the center seat.
George: 2 choices -- either side of Dahlia.

After that, there are no restrictions. There are 5 seats left; the number of ways to fill them with no restrictions is 5*4*3*2*1 = 120.

So the total number of different orders is 1*2*120 = 240.