SOLUTION: 1/1−sin(x)=sec^2(x)+sec(x)tan(x)
Hi tutors, i already solve this identity by RHS, but now i want to solve it by LHS, but i got stuck at the very beginning which like
1/1
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-> SOLUTION: 1/1−sin(x)=sec^2(x)+sec(x)tan(x)
Hi tutors, i already solve this identity by RHS, but now i want to solve it by LHS, but i got stuck at the very beginning which like
1/1
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Question 1114589: 1/1−sin(x)=sec^2(x)+sec(x)tan(x)
Hi tutors, i already solve this identity by RHS, but now i want to solve it by LHS, but i got stuck at the very beginning which like
1/1-sinx = /1-sinx * 1-sinx/1-sinx = 1-sinx/(1-sinx)^2
can someone give me some hints to continue this works ? thank you! Answer by josgarithmetic(39630) (Show Source):