SOLUTION: two cars are leaving Charlotte at the same time. -one car is moving east and the other west. -after 4 hours, the cars are 456 miles apart. -one car is traveling 10 miles per hou

Algebra ->  Customizable Word Problem Solvers  -> Travel -> SOLUTION: two cars are leaving Charlotte at the same time. -one car is moving east and the other west. -after 4 hours, the cars are 456 miles apart. -one car is traveling 10 miles per hou      Log On

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Question 1114534: two cars are leaving Charlotte at the same time.
-one car is moving east and the other west.
-after 4 hours, the cars are 456 miles apart.
-one car is traveling 10 miles per hour faster than the other.
what is the speed of the slower-moving car?

Answer by ikleyn(52776) About Me  (Show Source):
You can put this solution on YOUR website!
.
Let r be the speed of the slower-moving car, in miles per hour.

Then the speed of the faster car is (r+10) mph.


The distance equation is


4r + 4*(r+10) = 456.


4r + 4r + 40 = 456

8r = 456-40 = 416  ====>  r = 416%2F8 = 52.


Answer.  The speed of the slower-moving car is 52 mph.

Solved.

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