SOLUTION: What are the two real solutions to {{{2^(x+2)*5^(6-x)=10^(x^2)}}}?

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Question 1114512: What are the two real solutions to 2%5E%28x%2B2%29%2A5%5E%286-x%29=10%5E%28x%5E2%29?
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
2%5E%28x%2B2%29%2A5%5E%286-x%29=2%5E%28x%5E2%295%5E%28x%5E2%29


system%28x%2B2=x%5E2%2Cand%2C6-x=x%5E2%29

system%28x%5E2-x-2=0%2Cand%2Cx%5E2%2Bx-6=0%29

system%28%28x-2%29%28x%2B1%29=0%2CAND%2C%28x%2B3%29%28x-2%29=0%29

ONE solution that should work is x=2.