SOLUTION: The intensity of a television signal varies indirectly as the square of the distance from the transmiter. If the intensity is 27 W/m^2 at a distance of 4.25 km, what is the inten

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Question 1114482: The intensity of a television signal varies indirectly as the square of the distance from the transmiter. If the intensity is 27 W/m^2
at a distance of 4.25 km, what is the intensity of a signal at a distance of 5.75? (round answer to two decimal places if needed)
Found 4 solutions by josgarithmetic, stanbon, josmiceli, ikleyn:
Answer by josgarithmetic(39620)   (Show Source):
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.... varies indirectly.....
?

Maybe one of these?
Intensity of tv signal varies directly as the square of distance from...
OR
Intensity of tv signal varies inversely as the square of distance from...
?

Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website!
The intensity of a television signal varies indirectly as the square of the distance from the transmiter. If the intensity is 27 W/m^2
at a distance of 4.25 km, what is the intensity of a signal at a distance of 5.75? (round answer to two decimal places if needed)
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i = k/d^2
Solve for "k"
27 = k/4.25^2
k = 27*4.25^2 = 487.6875
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Equation:
i = 487.6875/5.75^2
i = 14.75
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Cheers,
Stan H.
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Answer by josmiceli(19441)   (Show Source):
You can put this solution on YOUR website!

W/m2
m
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The intensity is 14.75 W/m2 at
a distance of 5.75 km
check the math

Answer by ikleyn(52814)   (Show Source):
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.
Physically correct formulation is

intensity of a television signal is inversely proportional to the square of the distance from the transmiter.