SOLUTION: Find all the real number roots of ln(x+1) - ln(x-1)=2

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: Find all the real number roots of ln(x+1) - ln(x-1)=2      Log On


   

Question 1114295: Find all the real number roots of ln(x+1) - ln(x-1)=2
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
ln(x+1) - ln(x-1)=2
ln((x+1)/(x-1)) = 2 = ln(e^2)
(x+1)/(x-1) = e^2
x+1 = e^2*x - e^2
x - x*e^2 = -1 - e^2
x*(e^2 - 1) = e^2 + 1
x+=+%28e%5E2+%2B+1%29%2F%28e%5E2+-+1%29