SOLUTION: find an equation of variation where y varies inversely as x and y =10 when x=15

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Question 1114255: find an equation of variation where y varies inversely as x and y =10 when x=15
Found 2 solutions by josmiceli, greenestamps:
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
+k+ = constant of proportionality
+y+=+k%2A%281%2Fx%29+
-------------------
given:
+y+=+10+
+x+=+15+
+10+=+k%2A%281%2F15%29+
+k+=+150+
--------------------
The equation is:
+y+=+150%2A%28+1%2Fx+%29+

Answer by greenestamps(13203) About Me  (Show Source):
You can put this solution on YOUR website!


While the formal solution by the other tutor using a constant of proportionality is fine, I find inverse variation far easier to work with and understand if I just think of the product of the two variables being constant.

In your example, y is 10 and x is 15; the product is 150.

So an equation showing that y is inversely proportional to x in your example is
xy = 150.

Which of course is equivalent to the other tutor's answer, y = 150/x.