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| Question 1114027:  In triangle ABC, length AB=32, length BC=10, and length AC=26. If line segment CH is the altitude to segment AB and segment CM is the median to AB, compute the length of line segment HM.
 Found 2 solutions by  ikleyn, greenestamps:
 Answer by ikleyn(52879)
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You can put this solution on YOUR website! . 
 
1.  Using the Heron's formula, calculate the area  S  of the triangle ABC.
    The side lengths are given.
2.  Next step find the length of the altitude CH from equation   = S.
3.  Consider right-angled triangle AHC.  In it, you know AC = 26. 
    In section 2 you just also found the length  |CH|.
    So you can find the leg  |AH|.
3.  Now you know  |AM|  (it is 16 units, half of  |AB|).
    You also know  |AH|.
    The difference  |AB|  minus  |AH|  is the length  |MH|  under the question.-----------------
 If you still have questions/comments, post them to me through the "Thank you" window/message/form. Then I will help/answer to you.
 
 If you do, then refer please to the problem ID number 1114027.
 
 Otherwise I will not know to whom to answer . . .
 
 
Answer by greenestamps(13209)
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