SOLUTION: How can I solve the following to find B A=10^((B-C)/D)*E*F

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Question 1114013: How can I solve the following to find B
A=10^((B-C)/D)*E*F
Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39621) About Me  (Show Source):
You can put this solution on YOUR website!
A=10^((B-C)/D)*E*F


A=10%5E%28%28B-C%29%2FD%29%2AE%2AF

A%2F%28EF%29=10%5E%28%28B-C%29%2FD%29

log%28%28A%2F%28EF%29%29%29=%28%28B-C%29%2FD%29%2Alog%28%2810%29%29

baseten,

%28%28B-C%29%2FD%29%2A1=log%28%28A%2F%28EF%29%29%29

%28B-C%29%2FD=log%28%28A%2F%28EF%29%29%29

B-C=%281%2FD%29log%28%28A%2FEF%29%29%29

highlight%28B=log%28%28A%2F%28EF%29%29%29%2BC%29

Answer by ikleyn(52817) About Me  (Show Source):
You can put this solution on YOUR website!
.
The solution by  @josgatithmetic is incorrect.  Below find the correct version. 

A=10^((B-C)/D)*E*F



A=10%5E%28%28B-C%29%2FD%29%2AE%2AF


A%2F%28EF%29+=+10%5E%28%28B-C%29%2FD%29


log%28%28A%2F%28EF%29%29%29 = %28B-C%29%2FD


B-C = D%2Alog%28%28A%2FEF%29%29%29


B = D%2Alog%28%28A%2F%28EF%29%29%29%2BC%29