SOLUTION: The first three consecutive terms of an exponential sequence are (x-1), 2x and (5x+3) respectively. 1.find the value of x. 2.find the common ratio. 3.find the sum of the first six

Algebra ->  Sequences-and-series -> SOLUTION: The first three consecutive terms of an exponential sequence are (x-1), 2x and (5x+3) respectively. 1.find the value of x. 2.find the common ratio. 3.find the sum of the first six       Log On


   



Question 1113863: The first three consecutive terms of an exponential sequence are (x-1), 2x and (5x+3) respectively. 1.find the value of x. 2.find the common ratio. 3.find the sum of the first six terms.
Answer by greenestamps(13203) About Me  (Show Source):
You can put this solution on YOUR website!


The ratio between the second and first terms is the same as the ratio between the third and second terms:

2x%2F%28x-1%29+=+%285x%2B3%29%2F%282x%29
5x%5E2-2x-3+=+4x%5E2
x%5E2-2x-3+=+0
%28x-3%29%28x%2B1%29+=+0

x+=+3 or x+=+-1

Both values of x produce geometric sequences; but one of them is not very interesting:

x=3: 2, 6, 18, ...
x=-1: -2, -2, -2, ...

For x=3, the common ratio is 3, and the sum of the first 6 terms is 2+6+18+54+162+486 = 728.

Since we only needed to find the sum of the first 6 terms, it was easy simply to find the terms and add them. We could have used the formula for the sum of a finite geometric sequence. Since the formula is useful when we need to find the sum of a large number of terms, it is a useful formula to know.

S%28n%29+=+%28a%281-r%5En%29%29%2F%281-r%29
where a is the first term and r is the common ratio.

For this problem,
S%286%29+=+%282%281-3%5E6%29%29%2F%281-3%29+=+%282%28-728%29%29%2F%28-2%29+=+728

The problem is not very interesting for the case where x=-1; in that case, the common ratio is 1, and the sum of the first 6 terms is 6(-2) = -12.