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Question 1113631: Greetings everyone I have this algebra graph scenario with 4 questions.
This is the graph https://www.dropbox.com/s/dh1iv9pymmxk2jj/20180401_143151.jpg?dl=0
Jada sells ground paprika.Her weekly profit (in dollars) as a function of the amount of paprika she sold that week (in kilograms) is graphed.
1.What is Jada's profit per week if she sells 60 kilograms of paprika?
2.Estimate, at least, how many kilograms (per week) of Paprikamust Jada sell to make a profit?
3.Determine the profit per kilogram per week after selling at least 35 kilogram.
4.Determine the loss per kilogram per week, after selling less than 35 kilogram.
Thanks for any help in advance
Answer by amalm06(224)   (Show Source):
You can put this solution on YOUR website! Represent profit as y and paprika as x.
Find the relationship between y and x by taking two points on the graph, e.g. (35,0) and (60,200).
m=(200/25)=8
200=(60)(8)+b, b=-280, so y=8x-280
1. y=8*60-280=$200 (Answer)
2. 8x-280>0 --> 8x > 280 --> x> 280/8= 35 kg (Answer)
3. 35*8-280=0 (Her profit is 0 if she sells 35 kg)
If she sells 36 kg, her profit is $8
If she sells 37 kg, her profit is $16
So the profit per kilogram for each additional unit sold is $8 (Answer)
4. If she sells 29 kg, her profit is -48
If she sells 28 kg, her profit is -56
So her loss per kilogram is -$8 (Answer)
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