SOLUTION: A piece of ice is 3' * 10.5" * 10.5". Specific gravity of ice is .92. ---------- SG --> units of grams/cc Determine: A) Amount of water in the ice. B) Weight of ice.

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Question 1113600: A piece of ice is 3' * 10.5" * 10.5". Specific gravity of ice is .92.
----------
SG --> units of grams/cc
Determine:
A) Amount of water in the ice.
B) Weight of ice.

3 * .875 * .875 = 2.296875 cu. ft. (Volume of ice).

Unsure how to solve. Non-homework.
Found 2 solutions by ikleyn, Alan3354:
Answer by ikleyn(52776) (Show Source):
You can put this solution on YOUR website!
.
This question

Determine amount of water in the ice

MAKES NO SENSE.

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comment from student: I will reword the question: How much water makes up the ice?
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My response: OK, it is much better. My calcs are below:

A) Volume of the piece of ice 3 * .875 * .875 = 2.296875 cu. ft. B) Weight of ice. Weight (or mass) = Vol*density Density of ice = 57.2 pounds/cu ft (Source: https://www.engineeringtoolbox.com/density-solids-d_1265.html ) W = 57.2*2.296875 W =~ 131.38 pounds = same as weight of water.

Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website!
A piece of ice is 3' * 10.5" * 10.5". Specific gravity of ice is .92.
Determine:
A) Amount of water in the ice.
3 * .875 * .875 = 2.296875 cu. ft. (Volume of ice).
B) Weight of ice.
Weight (or mass) = Vol*density
Density of water = 62.372 pounds/cu ft
W = 62.372*2.296875*0.92
W =~ 131.8 pounds
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