SOLUTION: A family bought 4 sodas at a movie theatre for a total of $9.30. they bought one small, one medium and one large and one jumbo size. the jumbo cause twice as much as the medium, t
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Question 1113592: A family bought 4 sodas at a movie theatre for a total of $9.30. they bought one small, one medium and one large and one jumbo size. the jumbo cause twice as much as the medium, the medium costs 70 cents more than the small and the large costs twice as much as the small. what are the price of each soda? Found 3 solutions by josgarithmetic, ikleyn, MathTherapy:Answer by josgarithmetic(39618) (Show Source):
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4 sodas at a movie theatre for a total of $9.30. they bought one small, one medium and one large and one jumbo size.
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the jumbo COSTS twice as much as the medium, the medium costs 70 cents more than the small and the large costs twice as much as the small.
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Find price of each.
system could start as
.
substituting for y and z, ----------equation in two variables, w and x.
Revise to the simpler system,
Use simple substituion:
Use this value for w to find all the other price values.
Let x = small soda cost/price), in dollars.
Then the medium soda costs (x+0.7);
the large soda costs 2x;
the jumbo size costs 2*(x+0.7).
x + (x+0.7) + 2x + 2*(x+0.7) = 9.30
x + x + 0.7 + 2x + 2x + 1.4 = 9.30
6x + 2.1 = 9.30
6x = 9.30 - 2.1 = 7.2 ====> x = = 1.2.
Thus small soda costs 1.2 dollars.
Based on it, calculate the cost of other sodas on your own.
The lesson to learn from the solution is THIS:
This problem is for one unknown. It is not for 4 unknowns and not for using systems of equations.
You can put this solution on YOUR website! one small, one medium and one large and one jumbo size. the jumbo cause twice as much as the medium, the medium costs 70 cents more than the small and the large costs twice as much as the small. what are the price of each soda?
With M being the price of the medium, jumbo = 2M, small = M - .7, and large = 2(M - .7), or 2M - 1.4
We then get: M + 2M + M - .7 + 2M - 1.4 = 9.3
6M - 2.1 = 9.3
6M = 11.4
Cost of each jumbo:
Cost of each small:
Cost of each large:
There it is!!! No COMPLEXITIES!