Question 1113508: (2w^5+16w^4-10w^3-4w^2)\w^2
Answer by mattizzyo(1)   (Show Source):
You can put this solution on YOUR website! your question (2w^5+16w^4-10w^3-4w^2)\w^2
is already okay because the denominators degree is higher than the numerator but if it was (2w^5+16w^4-10w^3-4w^2)/w^2
then we would divide using long division method.
2w^3+16w^2-10w-4 -quotient
w^2 | 2w^5+16w^4-10w^3-4w^2
- | 2w^5
0. 16w^4
16w^4
0. -10w^3
-10w^3
0. -4w^2
-4w^2
0.
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