SOLUTION: Hello!
A ball is thrown off of the top of a 112 ft building. The height "h" of the ball (in feet) at any time "t" (in seconds) is given by the function:
h(t)= -16t^2+96t+112
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A ball is thrown off of the top of a 112 ft building. The height "h" of the ball (in feet) at any time "t" (in seconds) is given by the function:
h(t)= -16t^2+96t+112
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Question 1113479: Hello!
A ball is thrown off of the top of a 112 ft building. The height "h" of the ball (in feet) at any time "t" (in seconds) is given by the function:
h(t)= -16t^2+96t+112
1) Find the maximum height the ball reaches. Answer by rothauserc(4718) (Show Source):
You can put this solution on YOUR website! the path of the ball is a parabola that curves downward
:
we want the y coordinate of the parabola's vertex
:
x coordinate = -b/2a = (-96)/(-2*16) = 3
:
y coordinate = h(t) = -16t^2 +96t +112
:
h(3) = -16(9) +96*3 +112 = 256 feet
:
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the maximum height the ball reaches is 256 feet
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