Question 1113244: Find the equation of the line passing through the point (2, 1) and
perpendicular to the line 2y = 7 – x
Found 2 solutions by solver91311, Alan3354:
Answer by solver91311(24713)   (Show Source):
You can put this solution on YOUR website!
Put the given equation into Slope-Intercept Form, namely 
Divide by 2 and rearrange the RHS:
Now the coefficient on  represents the slope of the straight-line graph of the equation.
The slopes of perpendicular lines are negative reciprocals of each other, so, since the slope of the given line is  , the slope of the desired line must be 2.
To derive an equation of a line given a slope and a point, use the Point-Slope form:
)
where ) is the given point and  is the given slope. For ) and  :
)
This is one possible equation that represents the desired line, however, note that it is impossible to find the equation of a line because for any given line the set of equations representing that line is uncountably infinite. Since you don't specify a form, I'll let you manipulate the answer to satisfy the requirements of your Algebra course.
 .
John
My calculator said it, I believe it, that settles it
Answer by Alan3354(69443)  (Show Source):
You can put this solution on YOUR website! Find the equation of the line passing through the point (2, 1) and
perpendicular to the line 2y = 7 – x
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Find the slope of 2y = 7 – x
The slope of lines perpendicular, m, is the negative inverse of the slope of 2y = 7 – x
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Use y-y1 = m*(x-x1) where (x1,y1) is the point.
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