Question 1113240: find the x intercepts of the parabola with vertex (-1,-16) and y intercept (0,-15). use equation (y-k)=a(x-h)^2
Found 2 solutions by Fombitz, Boreal:
Answer by Fombitz(32388)   (Show Source):
Answer by Boreal(15235)  (Show Source):
You can put this solution on YOUR website! y=a(x-h)^2+k is the standard form, so h=-1 and k=-16
y=a(x+1)^2-16
putting (-1, -16) into vertex makes y+16=a(x+1)^2
x intercepts are where y=0. Where y=-15, x=0, so 1=a(1)^2. Therefore, a=1
a(x+1)^2=16
x+1=+/-4, since a=1
x=3, -5
(3, 0) and (-5, 0) ANSWER
The parabola is x^2+2x-15
That gives a vertex of (-1, -16) and the y-intercept of -15
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