Question 1113005: conrad has a collection of three types of coins: nickels, dimes, and quarters. there is an equal amount of nickels and quarters but three times as many dimes. if the entire collection is worth $9.60, how many nickels,dimes,and quarters are there?
Found 2 solutions by Boreal, greenestamps:
Answer by Boreal(15235)   (Show Source):
You can put this solution on YOUR website! nickels and quarters are each x
dimes are 3x
.05x+.10(3x)+.25x=9.60
.60x=9.60
x=16 nickels and 16 quarters ($4.80)
3x=48 dimes ($4.80)
Answer by greenestamps(13200)  (Show Source):
You can put this solution on YOUR website!
Since the numbers of nickels and quarters is the same and the number of dimes is 3 times as much, you can separate the coins into "mini-collections" each consisting of 1 nickel, 1 quarter, and 3 dimes.
The value of each of those mini-collections is 5+25+30 = 60 cents.
Since the total value of the coins is $9.60 (960 cents), the number of mini-collections you could make is 960/60 = 16.
Then since each of the mini-collections contains 1 nickel, 1 quarter, and 3 dimes, the answer to the problem is
16 nickels
16 quarters
3*16=48 dimes
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