Question 1112965: Can someone help? Thank you.
A ship leaves port and travels along a bearing of S 25 degree W for 18km, then turns on a bearing of S 65 degree E for 25km.
a. How far from port is this ship at the end of these two legs of the trip?
b. On what bearing must the ship travel to return to port?
Answer by Boreal(15235)   (Show Source):
You can put this solution on YOUR website! If this is drawn out, it is a right triangle with legs of 18 and 25 with the hypotenuse the distance from port
hypot^2+18^2+25^2=949
hypot=30.81 km
The angle centered on the port has two parts, one the departure S 25 W, and the other the return bearing.
The tangent of that angle equals 25/18, so the angle is 54.25 deg
The bearing away from the port is S 29.25 deg E (the difference). The bearing is the reciprocal.
Converting to degrees, the bearing away from the port is 150.75 deg, so the bearing towards the port is 330.75 deg or W 60.75 N.
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