SOLUTION: the sum and product of the three numbers in a Geometric progression are 28 and 512 respectively. what are the three numbers
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Question 1112803: the sum and product of the three numbers in a Geometric progression are 28 and 512 respectively. what are the three numbers Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! the sum and product of the three numbers in a Geometric progression are 28 and 512 respectively. what are the three numbers
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a, ar, ar^2
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a(1+r+r^2) = 28
(ar)^3 = 512
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ar = cbrt(512) = 8
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If a = 1 ; r = 8 then product = (ar)^3 = 512 and sum = 1(1+8+64) # 28
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If a = 2 ; r = 4 then product = 512 and sum = 2(1+4+16) = 84
If a = 4 ; r = 2 then product = 512 and sum 4(1+2+4) = 28
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Cheers,
Stan H.
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