SOLUTION:
On a Friday night, 26% of the students at a university go out for pizza, 10% see a movie, 26% go to a party, and 38% stay home to study. 24 students are randomly selected. Can t
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On a Friday night, 26% of the students at a university go out for pizza, 10% see a movie, 26% go to a party, and 38% stay home to study. 24 students are randomly selected. Can t
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Question 1112741:
On a Friday night, 26% of the students at a university go out for pizza, 10% see a movie, 26% go to a party, and 38% stay home to study. 24 students are randomly selected. Can the probability that exactly 7 out of these students stay home be computed using a binomial model? Answer by solver91311(24713) (Show Source):
Yes, because there are two possible outcomes, one that would be considered a successful outcome of the experiment and the other a failed outcome and the probability of success for any given trial is constant.
However, in view of the fact that your given data is ambiguous in one sense, there will be two possible answers to the question.
Does "see a movie" mean to put on a DVD and STAY HOME to watch it? Or does it mean GO OUT to a theater? In the first case, the chance of success on a given trial is 48%. In the second case, the chance of success on a given trial is 38%.
John
My calculator said it, I believe it, that settles it
