Question 1112728: Help me to Solve this A Confidence Interval for a Population Proportion Problem ! Need help for question B
The Fox TV network is considering replacing one of its prime-time crime investigation shows with a new family-oriented comedy show. Before a final decision is made, network executives commission a sample of 350 viewers. After viewing the shows, 250 indicated they would watch the new show and suggested it replace the crime investigation show.
A) Estimate the value of the population proportion. (Round your answers to 3 decimal places.) (i already found the answer i think its 0.714)
B)Develop a 90% confidence interval for the population proportion. (Use z Distribution Table.) (Round your answers to 3 decimal places.)
Confidence interval ........ and ........,
Answer by rothauserc(4718)   (Show Source):
You can put this solution on YOUR website! B) standard error(SE) = square root(0.714 * (1-0.714)/350) = 0.024
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alpha(a) = 1 - (90/100) = 0.10
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critical probability(p*) = 1 - (a/2) = 0.95
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critical value(CV) is the z-score corresponding to p*, CV = 1.645
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margin of error(ME) = CV * SE = 1.645 * 0.024 = 0.0395 approximately 0.040
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90% confidence interval is 0.714 + or - 0.040 or (0.674, 0.754)
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