SOLUTION: The length of a rectangle is 3yd less than twice the width, and the area of the rectangle is 27yd^2 . Find the dimensions of the rectangle.

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Question 1112550: The length of a rectangle is 3yd less than twice the width, and the area of the rectangle is 27yd^2 . Find the dimensions of the rectangle.
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Dimensions 2w-3 and w

w%282w-3%29=27
2w%5E2-3w=27
2w%5E2-3w-27=0
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w=%283%2B-+sqrt%289%2B4%2A2%2A27%29%29%2F4
w=%283%2B15%29%2F4
w=18%2F4
w=9%2F2=4%261%2F2 width
.
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Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

The length of a rectangle is 3yd less than twice the width, and the area of the rectangle is 27yd^2 . Find the dimensions of the rectangle.
Correct answer: Width:  4.5 yds

                Length: 6 yds