SOLUTION: The distance (in km) an object has fallen since it enters the earth's atmosphere is given by: s(t)= (5,000/t+1)-50,000. After the object has traveled for 10 seconds after enteri

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: The distance (in km) an object has fallen since it enters the earth's atmosphere is given by: s(t)= (5,000/t+1)-50,000. After the object has traveled for 10 seconds after enteri      Log On

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Question 1112526: The distance (in km) an object has fallen since it enters the earth's atmosphere is given by: s(t)= (5,000/t+1)-50,000.
After the object has traveled for 10 seconds after entering the atmosphere, find:
A) The distance it has fallen
B) Velocity
C) Acceleration
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
s(t)= (5,000/t+1)-50,000.
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Is it (5000/t) + 1 ?
Or 5000/(t+1) ?