SOLUTION: A tall cylindrical container 6cm in diameter contains some water. Nine steel spheres of diameter 4cm are put into the water. If all the spheres are under water, and no water overfl

Algebra ->  Geometry-proofs -> SOLUTION: A tall cylindrical container 6cm in diameter contains some water. Nine steel spheres of diameter 4cm are put into the water. If all the spheres are under water, and no water overfl      Log On


   

Question 1112515: A tall cylindrical container 6cm in diameter contains some water. Nine steel spheres of diameter 4cm are put into the water. If all the spheres are under water, and no water overflows from the container, then the rise in water level in cm, is
Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39630) About Me  (Show Source):
You can put this solution on YOUR website!
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tall cylindrical container 6cm in diameter contains some water.....
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Volume of the nine spheres:
4%2A%284%2F3%29pi%2A%286%2F2%29%5E3

%28%284%2A4%2A6%2A6%2A6%29%2F%283%2A2%2A2%2A2%29%29pi

pi%2A%282%5E4%2A2%5E3%2A3%5E3%29%2F%283%2A2%5E3%29
pi%282%5E4%2A3%5E2%29

144pi--------volume of the spheres
-
h, change in water height in the cylinder before and after adding spheres:
h%2Api%2A3%5E2=144pi
h=144%2F9
highlight%28h=16%29 centimeters

Answer by ikleyn(52884) About Me  (Show Source):
You can put this solution on YOUR website!
.
.
1.  There is special lesson in this site
          - Water level rise in a tank after submerging bodies
     devoted to this kind of problems.

     It explains the solution method and an idea in all details and gives many examples.


2.  This (or similar) problem came to the forum at least twice and was solved and explained under these links

          https://www.algebra.com/algebra/homework/word/geometry/Geometry_Word_Problems.faq.question.1112243.html

          https://www.algebra.com/algebra/homework/Volume/Volume.faq.question.1112271.html


I just tired to explain it again and again.

Do not expect that I will do calculations for you or instead of you.   I will not !

I just explained  EVERYTHING  under the given links.

The rest is on you !


                    H a p p y   l e a r n i n g  ! !


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@josgarithmetic !

Let's do an agreement:  I am responsible for these problems in this forum,  and you do not invade in/(do not touch) this area.

- Why ?

I think it does not require explanations.  In this way we will avoid unnecessary collisions.

Everybody/(everyone) will be happy.

=================

To the "student":

@josgarithmetic violated the agreement that I proposed to him and,

as usual, @josgaritmetic did all calculations INCORRECTLY.

In future, when/if you get something from @josgarithmetic,

keep in mind that with 30% - 50% probability it is incorrect.


So do not hurry to accept his solution - with high probability it is WRONG.