SOLUTION: Rajesh's temperature T (in degrees Fahrenheit) during a recent illness over the course of t hours is given by T(t)=98.6 + 4t/t^2 +1 a.) Find the rate of change of the temperatur

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Question 1112474: Rajesh's temperature T (in degrees Fahrenheit) during a recent illness over the course of t hours is given by T(t)=98.6 + 4t/t^2 +1
a.) Find the rate of change of the temperature with respect to time.
b.) Find the temperature at t=2.
c.) Find the rate of change of the temperature after 2 hours.

Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!


If his temperature is really 98.6%2B4t%2Ft%5E2%2B1, then shortly after time 0 his temperature is hotter than the surface of the sun.

So I assume you really mean his temperature is 98.6%2B4t%2F%28t%5E2%2B1%29. So

T%28t%29+=+98.6%2B4t%2F%28t%5E2%2B1%29


Answer a: dT%2Fdt+=+%284-4t%5E2%29%2F%28t%5E2%2B1%29%5E2

Answer b: T%282%29+=+98.6%2B4%282%29%2F%282%5E2%2B1%29+=+98.6%2B8%2F5+=+98.6%2B1.6+=+100.2

Answer c: dT/dt at t=2 = %284-4%282%5E2%29%29%2F%282%5E2%2B1%29%5E2+=+%284-16%29%2F%285%5E2%29+=+-12%2F25