SOLUTION: dewin has 4.35 in nickels and quarters. The number of quarters is 3 fewer than the number of nickels. how many of each coin does she have?

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: dewin has 4.35 in nickels and quarters. The number of quarters is 3 fewer than the number of nickels. how many of each coin does she have?      Log On


   



Question 1112448: dewin has 4.35 in nickels and quarters. The number of quarters is 3 fewer than the number of nickels. how many of each coin does she have?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
dewin has 4.35 in nickels and quarters. The number of quarters is 3 fewer than the number of nickels. how many of each coin does she have?
-----
Equations:
Value:: 5n + 25q = 435 cents
q = n - 3
-------------------
Modify::
n + 5q = 87
------
Substitute::
n + 5(n-3) = 87
6n = 102
n = 17 (# of nickels)
-----
q = n-3 = 14 (# of quarters)
-----------
Cheers,
Stan H.
----------