SOLUTION: Nine solid metal spheres, each of radius 2 cm, are dropped into a cylinder partly filled with water. If the spheres are totally immersed, find the increase in the height of the wat

Algebra ->  Volume -> SOLUTION: Nine solid metal spheres, each of radius 2 cm, are dropped into a cylinder partly filled with water. If the spheres are totally immersed, find the increase in the height of the wat      Log On


   



Question 1112271: Nine solid metal spheres, each of radius 2 cm, are dropped into a cylinder partly filled with water. If the spheres are totally immersed, find the increase in the height of the water if the radius of the cylinder is 3 cm.
Found 2 solutions by ikleyn, Boreal:
Answer by ikleyn(52803) About Me  (Show Source):
You can put this solution on YOUR website!
.
I just solved very similar problem today under the link
https://www.algebra.com/algebra/homework/word/geometry/Geometry_Word_Problems.faq.question.1112243.html

https://www.algebra.com/algebra/homework/word/geometry/Geometry_Word_Problems.faq.question.1112243.html


The water level rise in the cylindrical vessel is equal to the volume of all immersed bodies (9 spheres in your case)
divided by the base area of the vessel.

Read that lesson and complete the solution on your own.

Now, when all the principles are explained to you, I hope you are able to solve ANY of similar problems on your own.

Also, I hope that you will not send more of the same type problems to the forum with 7, 8 or 29 spherical balls, or whichever it is.



I love such problems, and I love to explain their solutions, but not more that 2 times to the same person.


Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
volume of each sphere is (4/3)*pi*r^3=(4/3)*pi*8, or 32pi/3 cm^3
9 of them are 96 pi cm^3 total volume
Volume of the container is pi*r^2*h=9*pi*h cm^3
96 pi/9 pi=h
h=96/9=10 2/3 or 32/3 cm. ANSWER