SOLUTION: Barney is buying tickets for a concert. He finds tickets for himself and his friends for $65 each plus a one time fee of $18. Betty is looking for tickets to the same concert. She

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: Barney is buying tickets for a concert. He finds tickets for himself and his friends for $65 each plus a one time fee of $18. Betty is looking for tickets to the same concert. She       Log On


   

Question 1112176: Barney is buying tickets for a concert. He finds tickets for himself and his friends for $65 each plus a one time fee of $18. Betty is looking for tickets to the same concert. She finds tickets at another website for $69 each and a one time fee of $10. How many tickets would need to be purchased by both Barney and Betty so that they spent the same amount?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Barney is buying tickets for a concert. He finds tickets for himself and his friends for $65 each plus a one time fee of $18. Betty is looking for tickets to the same concert. She finds tickets at another website for $69 each and a one time fee of $10. How many tickets would need to be purchased by both Barney and Betty so that they spent the same amount?
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Barney cost:: 18 + 65x
Betty cost::: 10 + 69x
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Solve:: 18+65x = 10+69x
4x = 8
x = 2 (# of tickets each one should buy)
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Cheers,
Stan H.
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