SOLUTION: I keep getting stuck on this problem (below is what I keep getting) The problem is....Solve for xby completing the square: x^2+6x=2 What I can get x^2+6x=2 6x^2=2 6(x^2)=2

Algebra ->  Equations -> SOLUTION: I keep getting stuck on this problem (below is what I keep getting) The problem is....Solve for xby completing the square: x^2+6x=2 What I can get x^2+6x=2 6x^2=2 6(x^2)=2       Log On


   



Question 111199: I keep getting stuck on this problem (below is what I keep getting)
The problem is....Solve for xby completing the square: x^2+6x=2
What I can get
x^2+6x=2
6x^2=2
6(x^2)=2
I cant get any further, can you please tell me what i did wrong. Thank you so much!!!!

Found 2 solutions by Earlsdon, solver91311:
Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Solve for x by completing the square:
x%5E2%2B6x+=+2 Complete the square in x by adding the square of half the x-coefficient to both sides, this is: %286%2F2%29%5E2+=+9
x%5E2%2B6x%2B9+=+2%2B9 Now factor the left side.
%28x%2B3%29%5E2+=+11 Now take the square root of both sides. You'll get two answers.
x%2B3+=+sqrt%2811%29 or x%2B3+=+-sqrt%2811%29 Now subtract 3 from both sides in each of these.
x+=+-3%2Bsqrt%2811%29 or x+=+-3-sqrt%2811%29 ...and these are the two roots.

Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!
x%5E2%2B6x=2
:
Follow this procedure to solve a quadratic by completing the square:
:
Step 1: Put the equation in the form ax%5E2%2Bbx=c. In this case you don't have to do anything because it is already in the proper form.
:
Step 2: Find divide the coefficient on the 'x' term by 2: 6/2 = 3
:
Step 3: Square this result: 3 * 3 = 9
:
Step 4: Add this result to both sides of the original equation
x%5E2%2B6x%2B9=11
:
Step 5: Factor the left side of the equation. This should be easy because you added the 9 to make the left side a perfect square.
%28x%2B3%29%5E2=11
:
Step 6: Take the square root of both sides and then add -3 to both sides. Don't forget that you need to consider both the positive and negative square roots.
x=-3%2B-sqrt%2811%29
x=-3%2Bsqrt%2811%29, or
x=-3-sqrt%2811%29