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If 35 mg of a radioactive element decays to 10mg in only 24 hours,
what is its half life?
:
the radioactive decay formula;
A = Ao*2^(-t/h)
where:
A = amt remain after t time
Ao = initial amt of the substance
t = time of decay
h = half-life of substance
:
A = 10
A = 35
t = 24 hrs
find h
35*2^(-24/h) = 10
2^(-24/h) = 10/35
2^(-24/h) = 2/7
log equiv of exponents log(2) = =
using the calc = -1.807355
h =
h = +13.28 hrs is the half life of the substance
