SOLUTION: How many square feet of tin are required to make a funnel, if the diameters of the top and bottom are 33 in. and 24 in., respectively, and the height is 23 in.?

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Question 1111890: How many square feet of tin are required to make a funnel, if the diameters of the top and bottom are 33 in. and 24 in., respectively, and the height is 23 in.?

Found 2 solutions by mananth, ikleyn:
Answer by mananth(16946) About Me  (Show Source):
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How many square feet of tin are required to make a funnel, if the diameters of the top and bottom are 33 in. and 24 in., respectively, and the height is 23 in.?
it is a frustum of a cone
surface area of frustum of cone= pi*(r+R)*l
l%5E2=x%5E2%2Bh%5E2%29
l%5E2=%283.5%29%5E2%2B%2823%29%5E2 =541.25
l= 23.3
surface area = 3.14*(12+16.5)*23.3 =2085.12 sq.in
square feet of tin required=2085.12 in^2

Answer by ikleyn(52887) About Me  (Show Source):
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.
It is a frustum of a cone.

Surface area of frustum of cone = 2pi%2AR%5Bave%5D%2Al,

    where R%5Bave%5D is the average radius (= arithmetic mean of r and R) and l is the slant height.

     We have  R%5Bave%5D = %28%2833%2F2%29%2B%2824%2F2%29%29%2F2 = 14.25 in,

              l = sqrt%28%2833%2F2-24%2F2%29%5E2%2B+23%5E2%29 = 23.43 in.


surface area = 2*3.14*14.25*23.43 =2096.75 sq.in

Area of tin  required = 2096.75 in^2