SOLUTION: tickets to a concert cost $20, $35, or $50 each. the number of $20 tickets sold was triple the number of $35 tickets sold. 400 more $50 tickets were sold than $35 tickets. if the t

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: tickets to a concert cost $20, $35, or $50 each. the number of $20 tickets sold was triple the number of $35 tickets sold. 400 more $50 tickets were sold than $35 tickets. if the t      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 1111865: tickets to a concert cost $20, $35, or $50 each. the number of $20 tickets sold was triple the number of $35 tickets sold. 400 more $50 tickets were sold than $35 tickets. if the tickets sold had a value of $150 500, how many of each type of ticket was sold?
Answer by ikleyn(52810) About Me  (Show Source):
You can put this solution on YOUR website!
.
Let x = # of the $35 tickets.

Then the # of the $20 tickets was 3x  and the number of the $50 tickets was (x+400).


Then your money equation is


35x + 20*(3x) + 50*(x+400) = 150500.


It is your basic equation. Simplify and solve it for x.