SOLUTION: Two trains leave towns 586 km apart at the same time and travel toward each other. One train travels 13 km/h slower than the other. If they meet in 2 hours, what is the rate of eac

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Question 1111845: Two trains leave towns 586 km apart at the same time and travel toward each other. One train travels 13 km/h slower than the other. If they meet in 2 hours, what is the rate of each train?
slower train:
Faster train:
Found 2 solutions by ikleyn, mananth:
Answer by ikleyn(52756)   (Show Source):
You can put this solution on YOUR website!
.
I just answered this question under this link
https://www.algebra.com/algebra/homework/coordinate/word/Linear_Equations_And_Systems_Word_Problems.faq.question.1111740.html

https://www.algebra.com/algebra/homework/coordinate/word/Linear_Equations_And_Systems_Word_Problems.faq.question.1111740.html

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            OK. I see that even some tutors of this forum are not able to solve it correctly. So I will do it for you.

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As I just wrote in my referred post, 2r + 2*(r+13) = 586 kilometers, where r is the slower train speed. It gives you 2r + 2r + 26 = 586 ====> 4r = 586-26 = 560 ====> r = = 140. Answer. The speed of the slower train is 140 km/h; the speed of the faster train is 140+13 = 153 km/h.

Solved.

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Answer by mananth(16946)   (Show Source):
You can put this solution on YOUR website!
Two trains leave towns 586 km apart at the same time and travel toward each other. One train travels 13 km/h slower than the other. If they meet in 2 hours, what is the rate of each train?
Distance apart 586 km
First train speed x
other train speed (x-13)
time = 2 hours
The trains are moving towards each other
add up the speeds
2x-13
t=d/s
2=860/(2x-13)
4x-26 =860
4x = 886
x= 886/4
x= 221.5 km/h One train
Other train 221.5-13= 208.5 km/h