SOLUTION: find three consecutive integers such that three times the smaller integer is eight more than the sum of the other two integers

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Question 1111787: find three consecutive integers such that three times the smaller integer is eight more than the sum of the other two integers
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
n, n+1, n+2

3n=8%2B%28n%2B1%29%2B%28n%2B2%29
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11, 12, 13