SOLUTION: Flying against the wind, an airplane travels 3240 km in 6 hours. Flying with the wind, the same plane travels 8160 km in 8 hours. What is the rate of the plane in still air and wha
Question 1111738: Flying against the wind, an airplane travels 3240 km in 6 hours. Flying with the wind, the same plane travels 8160 km in 8 hours. What is the rate of the plane in still air and what is the rate of the wind? Answer by ikleyn(52853) (Show Source):
Let u = airplane speed at no wind and v = the wind speed.
Then
= 540 is effective speed against the wind, which is the difference u-v:
u - v = 540 (1)
= 1020 is effective speed with the wind, which is the sum u+v:
u + v = 1020 (2)
Add equations (1) and (2) to get
2u = 1560 ====> u = = 780 km/h is the airplane speed at no wind.
Then from (1) v = 1020 - 780 = 240 km/h for the wind.
This result for the wind TELL you that the problem is very BADLY DESIGNED, because 240 km/h is more than an hurricane speed
and any flights are prohibited under such conditions.
I don't like very much to work with badly designed problems.
My personal opinion is that their creators deserve a punishment.