Question 1111654: Log10(xsquaare-4x+7)=2
Answer by rothauserc(4718)   (Show Source):
You can put this solution on YOUR website! log(base 10) (x^2 -4x +7) = 2
:
use definition of logarithms
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x^2 -4x +7 = 10^2 = 100
:
x^2 -4x -93 = 0
:
x^2 -4x = 93
:
x^2 -4x +4 = 93 +4 = 97
:
(x-2)^2 = 97
:
x-2 = square root(97)
:
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x = 2 + square root(97)
x = 2 - square root(97)
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