SOLUTION: Suppose a circular fish pond has to be sealed on the inside. The diameter of the pond is 3 metres and the depth is 1 1/2 metres. One litre of sealer covers 3 square metres. How ma

Algebra ->  Customizable Word Problem Solvers  -> Finance -> SOLUTION: Suppose a circular fish pond has to be sealed on the inside. The diameter of the pond is 3 metres and the depth is 1 1/2 metres. One litre of sealer covers 3 square metres. How ma      Log On

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Question 1111448: Suppose a circular fish pond has to be sealed on the inside. The diameter of the pond is 3 metres and the
depth is 1 1/2 metres. One litre of sealer covers 3 square metres. How many two-litre tins of sealer have to be
purchased to complete the sealing job?
1] 8
[2] 7
[3] 3
[4] 4
please correct my answer
Pie 3.14
Diameter = 3
Depth = 1 1/2
3.14 x 1.5*2 x 1 1/2
= 3, 5325
= 4

Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
This is the area of a hemisphere
That would be (1/2)*4pi*r^2=(1/2)4pi1.5^2=4.5 pi=14.14 m^2
7 would almost do it.
8 are needed.
(4)