SOLUTION: Find the minimum slope of the line tangent to the curve y = x³-3x²+6x+3.

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Question 1111345: Find the minimum slope of the line tangent to the curve y = x³-3x²+6x+3.
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
derivative of x^3-3x^2+6x+3 is 3x^2-6x+6
The derivative is the slope of the line. The minimum value is where x=-b/2a, like any quadratic.
That is x=6/6=1
The slope is 3-6+6 or 3. The point on the original function is (1, 7)
graph%28300%2C300%2C-10%2C10%2C-10%2C10%2Cx%5E3-3x%5E2%2B6x%2B3%2C3x%5E2-6x%2B6%29