SOLUTION: Joe and Al work together for 4 hours to fix a car. If joe works alone, he can fix the car in 6 hours. How long will it take Al to fix the car by himself?

Algebra ->  Rate-of-work-word-problems -> SOLUTION: Joe and Al work together for 4 hours to fix a car. If joe works alone, he can fix the car in 6 hours. How long will it take Al to fix the car by himself?      Log On


   



Question 1111315: Joe and Al work together for 4 hours to fix a car. If joe works alone, he can fix the car in 6 hours. How long will it take Al to fix the car by himself?
Answer by ikleyn(52769) About Me  (Show Source):
You can put this solution on YOUR website!
.
Working together,  they do 1%2F4 of the job per hour.


Working alone, Joe does 1%2F6 of the job per hour.


Hence, Al does  1%2F4 - 1%2F6 = 3%2F12 - 2%2F12 = 1%2F12 of the work per hour.


It means Al needs 12 hours to complete the job working alone.

---------------
It is a typical joint work problem.

There is a wide variety of similar solved joint-work problems with detailed explanations in this site.  See the lessons
    - Using Fractions to solve word problems on joint work
    - Solving more complicated word problems on joint work
    - Selected joint-work word problems from the archive


Read them and get be trained in solving joint-work problems.

Also,  you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this textbook under the topic
"Rate of work and joint work problems"  of the section  "Word problems".


Save the link to this online textbook together with its description

Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson

to your archive and use it when it is needed.