SOLUTION: Two cars, A and B, 148 kilometers apart, traveled toward each other. A started at 6 a.m. while B started an hour later. They met on the road at 9 a.m. Had both of them started at 6

1.  In the first scenario, 1-st car was on the way 3 hours (from 6 am till 9 am) before meeting.

                           2-nd car was on the way 2 hours before meeting.


    Let "a" and "b" be their rates in miles per MINUTE, respectively. 

    Then from the first scenario, the total distance between the cities was

        180a + 120b  = 148  miles.               (1)    (3 hours = 180 minutes;  2 hours = 120 minutes !)



2.  In the second scenario, each car was on the way 2 hours and 28 minutes = 148 minutes.  


    Therefore, the second equation for the entire distance is

        148a + 148b = 148  miles,   or

           a + b = 1       (miles per minute)     (2) 



3.  Thus you have this system of two equations in two unknowns

       a +    b =   1,    and

    180a + 120b = 148.


    Solve it by ANY method you want.  Both methods - Substitution and Elimination - are good.  Choose any and complete the solution on your own.



4.   H a p p y   s o l v i n g  ! !