SOLUTION: Problem Page A jet travels 6096 mi against a jetstream in 8 hours and 7056 with the jetstream in the same amount of time. What is the rate of the jet in still air and what is the r

Let x = the jet rate at no wind (in mph), and

    y = the rate of the wind.


Then the effective rate of the jet with the wind is x + y mph,
while the effective rate of the jet with the wind is x - y mph.


The condition says

 = x - y     (the effective speed against the wind)

 = x + y     (the effective speed with the wind)


After calculations, it takes the form


x - y = 762     (1)

x + y = 882     (2)
---------------------- Add the equations

2x = 762 + 882 = 1644    ====>  x =  = 822 mph.   It is the rate of the jet at no wind.


Then from eq(2),  y = 882 - 822 = 60 mph  is the rate of the wind.